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Rating Normalization

Recommender Systems

Easy

Rating normalization removes differences in how generously or strictly users assign ratings. Given a user-item matrix where 0 represents an unrated item, subtract each user's mean observed rating from that user's rated entries. Keep every unrated entry at 0.

For each user, compute the mean of the nonzero ratings:

\bar{r}_u = \frac{1}{|\mathcal{I}_u|}\sum_{i \in \mathcal{I}_u}r_{ui}

Here, u identifies a user, i identifies an item, r_{ui} is the user's rating for that item, and the rated-item set contains every item rated by user u.

Normalize each matrix entry:

\hat{r}_{ui} = \begin{cases} r_{ui} - \bar{r}_u & \text{if } r_{ui} \ne 0 \\ 0 & \text{otherwise} \end{cases}

Return the normalized matrix as a list of user rows rounded to six decimals for display.

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Examples

Input: matrix = [[5, 3, 0, 1], [4, 0, 0, 1], [1, 1, 0, 5]]

Output: [[2.0, 0.0, 0.0, -2.0], [1.5, 0.0, 0.0, -1.5], [-1.333333, -1.333333, 0.0, 2.666667]]

Explanation: Each nonzero rating is shifted by its user’s mean, while unrated zeros remain zero.

Input: matrix = [[2, 4, 6]]

Output: [[-2.0, 0.0, 2.0]]

Hint 1

Collect the nonzero ratings from one row before computing its mean.

Hint 2

Subtract that mean only from rated entries and keep unrated entries at zero.

Requirements

For each user, compute the mean of their non-zero (rated) entries
Subtract the user's mean from each of their rated entries
Leave unrated entries (0) as 0.0
If a user has no ratings, all entries remain 0.0
Return the normalized matrix as a list of lists of floats

Constraints

matrix is a non-empty list of lists (user × item)
Values are non-negative numbers; 0 means unrated
Return a list of lists of floats
Time limit: 300 ms

Try Similar Problems

Mean Rating Imputation Adjusted Cosine Similarity Zscore Standardization Matrix Normalization Baseline Predictor

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Rating Normalization

Recommender Systems

Easy

For each user, compute the mean of the nonzero ratings:

\bar{r}_u = \frac{1}{|\mathcal{I}_u|}\sum_{i \in \mathcal{I}_u}r_{ui}

Here, u identifies a user, i identifies an item, r_{ui} is the user's rating for that item, and the rated-item set contains every item rated by user u.

Normalize each matrix entry:

\hat{r}_{ui} = \begin{cases} r_{ui} - \bar{r}_u & \text{if } r_{ui} \ne 0 \\ 0 & \text{otherwise} \end{cases}

Return the normalized matrix as a list of user rows rounded to six decimals for display.

Loading visualization...

Examples

Input: matrix = [[5, 3, 0, 1], [4, 0, 0, 1], [1, 1, 0, 5]]

Output: [[2.0, 0.0, 0.0, -2.0], [1.5, 0.0, 0.0, -1.5], [-1.333333, -1.333333, 0.0, 2.666667]]

Explanation: Each nonzero rating is shifted by its user’s mean, while unrated zeros remain zero.

Input: matrix = [[2, 4, 6]]

Output: [[-2.0, 0.0, 2.0]]

Hint 1

Collect the nonzero ratings from one row before computing its mean.

Hint 2

Subtract that mean only from rated entries and keep unrated entries at zero.

Requirements

For each user, compute the mean of their non-zero (rated) entries
Subtract the user's mean from each of their rated entries
Leave unrated entries (0) as 0.0
If a user has no ratings, all entries remain 0.0
Return the normalized matrix as a list of lists of floats

Constraints

matrix is a non-empty list of lists (user × item)
Values are non-negative numbers; 0 means unrated
Return a list of lists of floats
Time limit: 300 ms

Try Similar Problems

Mean Rating Imputation Adjusted Cosine Similarity Zscore Standardization Matrix Normalization Baseline Predictor

Case 1

Case 2

matrix =

Accepts: array

For each user, compute the mean of the nonzero ratings:

\bar{r}_u = \frac{1}{|\mathcal{I}_u|}\sum_{i \in \mathcal{I}_u}r_{ui}

Here, u identifies a user, i identifies an item, r_{ui} is the user's rating for that item, and the rated-item set contains every item rated by user u.

Normalize each matrix entry:

\hat{r}_{ui} = \begin{cases} r_{ui} - \bar{r}_u & \text{if } r_{ui} \ne 0 \\ 0 & \text{otherwise} \end{cases}

Return the normalized matrix as a list of user rows rounded to six decimals for display.